nguyenhappy92

Tính S(n) = 1 + 1/3 + 1/5 + ... + 1/n

Sep 16th, 2015
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  1. // Tính S(n) = 1 + 1/3 + 1/5 + ... + 1/n
  2. // Khai bao thu vien
  3. #include<stdio.h>
  4. #include<conio.h>
  5.  
  6. void main()
  7. {
  8. // khai bao bien
  9. int n;
  10. // nhap du lieu
  11. scanf("%d",&n);
  12. float s=0;
  13. for(int i=1;i<=n;i++)
  14. {
  15. if(n%2!=0)
  16. {
  17. s=s+(float) 1/i;
  18. }
  19. }
  20. printf("%.2f",s);
  21. }
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