passing data using hyperlink in PHP
<?php

$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name=""; // Table name

// Connect to server and select databse.
mysql_connect($host, $username, $password)or die("cannot connect");
mysql_select_db($db_name) or die("cannot select DB");


$photo=mysql_query("SELECT * FROM `images` ORDER BY (ID = 11) DESC, RAND() LIMIT 7");

while($get_photo=mysql_fetch_array($photo)){ ?>

<div style="width:300px;">


<a href="does_this_work.php?big_image=$get_photo['guest']>" target=""><img src="<?
echo $get_photo['url']; ?>" title="">


 </div>

 <? } ?>

<?php

echo "this is the page where you get a larger picture of image on previous page, plus
further info";

$big_image = $_GET['guest'];

echo $big_image;

?>

//The variable must not necessarily be $value
$value = $_GET['argument'];
//Alt.
$value = $_POST['argument'];

<a href="does_this_work.php?big_image=$get_photo['guest']>" target=""><img src="<? echo $get_photo['url']; ?>" title="">

<a href="does_this_work.php?big_image=<?php echo $get_photo['guest']; ?>" target=""><img src="<?php echo $get_photo['url']; ?>" title="">

<a href="does_this_work.php?guest=<?php echo $get_photo['guest']; ?>" target=""><img src="<?php echo $get_photo['url']; ?>" title="">

<a href="does_this_work.php?big_image=$get_photo['guest'] ?>"

<a href="does_this_work.php?big_image=<?= $get_photo['guest']; ?>"

<a href="does_this_work.php?big_image=$get_photo['guest'] ?>" target=""><img src="<?
echo $get_photo['url']; ?>" title="">

<a href="does_this_work.php?big_image=<? $get_photo['guest'] ?>" target=""><img src="<?
echo $get_photo['url']; ?>" title="">