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- def c(se,t):return"\033[38;2;{};{};{}m{} \033[38;2;255;255;255m".format(se[0], se[1], se[2], t)
- l=16 # aspect ratio = 3:2, multiples of 7 that exceed 7 (i.e. 14, 28, etc.) work the best!
- a=l*l*1.5
- for i in range(1,int(a)+1): print(c([255,215,0] if i>.5*a else [0,87,183],'UKRAINE'[(i-1)%7]),end="" if i%(a/l)!=0 else "\n")
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