A bracelett mixed out of material a and b is lowered into water. Outside it weights 0.49N, in the water it weights 0.44N, due to buoyancy force. Calculate mass of object a and object b in the bracelett.
Fg=0.49NA=0.049949kg=49.949g
Fg(measured in H20)=0.44N
Fg(difference)=0.05N=buoyancy force
density_a=8.9g/cc
density_b=19.3g/cc
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V=(F_buoyancy)/(density*gravity) = 0.05/(1g/cc*9.81m/s^2)=0.0051cc
density_sum= m/V = 0.049949g/0.0051cc = 9.79g/cc
density_sum=(density_a*a)+(density_b*(1-a) => a = (density_sum - density_b)/(density_a - density_b) => a=0.9144 => b=0.0866
mass(a)=46g
mass(b)=4.33g