#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

int main() {
  ll r;
  cin >> r;
  for (ll x = 1; x * x + x + 1 <= r; ++x) {
    ll y = (r - ((x * x) + x + 1)) / (2 * x);
    if (!x || !y) {
      continue;
    }
    if ((x * x) + (2 * x * y) + x + 1 == r) {
      cout << x << ' ' << y;
      return 0;
    }
  }
  cout << "NO";
  return 0;
}