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- 50mA przez 10 sek co 3h
- 0.01mA przez resztę czasu
- 2610mAh pojemność baterii
- 50mA*10sek 0.01mA*10790sek 500mAs 107.9mAs
- ------------ + ------------------- = -------- + ---------- = 0.046mA+0.00999mA = 0.05599mA
- 3*3600sek 3*3600sek 10800s 10800s
- Średni pobór prądu wynosi 0.05599mA
- 2610mAh / 0.05599mA = 46615.46h = 5.3213995434 years
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