Revrese Integer with overflow condition.

#include <iostream>
#include <vector>

using namespace std;

class Solution {
public:
    int reverse(int x) {
        long long rev = 0;
        while (x)
        {
            rev *= 10;
            rev += (x % 10);
            x /= 10;
        }
        return ((rev > INT_MAX || rev < INT_MIN) ? 0 : rev);
    }
};

int main(void)
{
    cout << "Number to reverse: ";
    int num; cin >> num;
    Solution s;
    int count = 0, original = num;
    while (num % 10 == 0) {
        ++count;
        num /= 10;
    }
    int reverseNum = s.reverse(num);

    cout << "\nReversed Number: ";

    if (reverseNum < 0) {
        cout << "-";
        reverseNum *= (-1);
    }
    for (int i = 0; i < count; i++)
    {
        cout << "0";
    }
    cout << reverseNum << "\n\n";
    return 0;
}