a53

simple

a53
Nov 20th, 2019
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  1. #include <cstdio>
  2. #include <cassert>
  3. #include <algorithm>
  4.  
  5. #define MAX 2000000000000000000LL
  6. #define pii pair <long long, long long>
  7.  
  8. using namespace std;
  9.  
  10. int v[200010];
  11. struct arb
  12. {
  13. long long mipar, mapar, miimp, maimp;
  14.  
  15. arb ()
  16. {
  17. mipar = miimp = MAX;
  18. mapar = maimp = 0LL;
  19. }
  20.  
  21. void operator+= (const long long &val)
  22. {
  23. if (val & 1)
  24. {
  25. swap (mipar, miimp);
  26. swap (mapar, maimp);
  27. }
  28.  
  29. if (mipar < MAX) mipar += val;
  30. if (miimp < MAX) miimp += val;
  31. if (mapar != 0LL) mapar += val;
  32. if (maimp != 0LL) maimp += val;
  33. }
  34.  
  35. } aint[800010];
  36.  
  37. long long lazy[800010];
  38.  
  39. void build (int a, int b, int nod)
  40. {
  41. if (a == b)
  42. {
  43. if (v[a] & 1) aint[nod].miimp = aint[nod].maimp = 1LL * v[a];
  44. else aint[nod].mipar = aint[nod].mapar = 1LL * v[a];
  45. return;
  46. }
  47.  
  48. int mij = (a + b) >> 1;
  49.  
  50. build (a, mij, nod << 1);
  51. build (mij + 1, b, nod << 1 | 1);
  52.  
  53. aint[nod].miimp = min (aint[nod << 1].miimp, aint[nod << 1 | 1].miimp);
  54. aint[nod].mipar = min (aint[nod << 1].mipar, aint[nod << 1 | 1].mipar);
  55. aint[nod].maimp = max (aint[nod << 1].maimp, aint[nod << 1 | 1].maimp);
  56. aint[nod].mapar = max (aint[nod << 1].mapar, aint[nod << 1 | 1].mapar);
  57. }
  58.  
  59. void propag (int st, int dr, int nod)
  60. {
  61. aint[nod] += lazy[nod];
  62.  
  63. if (st != dr)
  64. {
  65. assert ((nod << 1 | 1) <= 800000);
  66. lazy[nod << 1] += lazy[nod];
  67. lazy[nod << 1 | 1] += lazy[nod];
  68. }
  69.  
  70. lazy[nod] = 0;
  71. }
  72.  
  73. void update (int st, int dr, int a, int b, int nod, int val)
  74. {
  75. propag (st, dr, nod);
  76.  
  77. if (a <= st && dr <= b)
  78. {
  79. lazy[nod] += 1LL * val;
  80. propag (st, dr, nod);
  81.  
  82. return;
  83. }
  84.  
  85. int mij = (st + dr) >> 1;
  86.  
  87. if (a <= mij) update (st, mij, a, b, nod << 1, val);
  88. else propag (st, mij, nod << 1);
  89.  
  90. if (b > mij) update (mij + 1, dr, a, b, nod << 1 | 1, val);
  91. else propag (mij + 1, dr, nod << 1 | 1);
  92.  
  93. aint[nod].miimp = min (aint[nod << 1].miimp, aint[nod << 1 | 1].miimp);
  94. aint[nod].mipar = min (aint[nod << 1].mipar, aint[nod << 1 | 1].mipar);
  95. aint[nod].maimp = max (aint[nod << 1].maimp, aint[nod << 1 | 1].maimp);
  96. aint[nod].mapar = max (aint[nod << 1].mapar, aint[nod << 1 | 1].mapar);
  97. }
  98.  
  99. pii query (int st, int dr, int a, int b, int nod)
  100. {
  101. propag (st, dr, nod);
  102.  
  103. if (a <= st && dr <= b) return pii(aint[nod].mipar, aint[nod].maimp);
  104.  
  105. int mij = (st + dr) >> 1;
  106.  
  107. pii rez1, rez2;
  108. rez1.first = rez2.first = MAX;
  109. rez1.second = rez2.second = 0;
  110.  
  111. if (a <= mij) rez1 = query (st, mij, a, b, nod << 1);
  112. if (b > mij) rez2 = query (mij + 1, dr, a, b, nod << 1 | 1);
  113.  
  114. rez1.first = min (rez1.first, rez2.first);
  115. rez1.second = max (rez1.second, rez2.second);
  116.  
  117. return rez1;
  118. }
  119.  
  120. int main ()
  121. {
  122. //freopen ("input", "r", stdin);
  123. //freopen ("output1", "w", stdout);
  124.  
  125. int n;
  126. scanf ("%d", &n);
  127.  
  128. assert (1 <= n && n <= 200000);
  129.  
  130. for (int i = 1; i <= n; ++i)
  131. {
  132. scanf ("%d", &v[i]);
  133. assert (1 <= v[i] && v[i] <= 2000000000);
  134. }
  135.  
  136. build (1, n, 1);
  137.  
  138. int q;
  139. scanf ("%d", &q);
  140.  
  141. assert (1 <= q && q <= 200000);
  142.  
  143. for (int i = 1; i <= q; ++i)
  144. {
  145. int op, a, b, val;
  146. scanf ("%d %d %d", &op, &a, &b);
  147.  
  148. assert (op == 0 || op == 1);
  149. assert (1 <= a && a <= n);
  150. assert (1 <= b && b <= n);
  151. assert (a <= b);
  152.  
  153. if (op == 0)
  154. {
  155. scanf ("%d", &val);
  156. assert (1 <= val && val <= 2000000000);
  157.  
  158. update (1, n, a, b, 1, val);
  159. }
  160.  
  161. else
  162. {
  163. pii rez = query (1, n, a, b, 1);
  164.  
  165. assert (0LL <= rez.first && rez.first <= MAX);
  166. assert (0LL <= rez.second && rez.second <= MAX);
  167.  
  168. if (rez.first >= MAX) rez.first = -1LL;
  169. if (rez.second == 0LL) rez.second = -1LL;
  170.  
  171. printf ("%lld %lld\n", rez.first, rez.second);
  172. }
  173. }
  174.  
  175. return 0;
  176. }
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