Mihai_Preda

Untitled

Jan 25th, 2023
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C++ 0.18 KB | None | 0 0
  1. int f(char s[100]) {
  2.   int nr = 0, i, n = strlen(s), p = 1;
  3.   for (i = 0; s[i] >= '0' && s[i] <= '9'; i++) {
  4.     nr = nr + p * (s[n - i - 1] - '0');
  5.     p *= 10;
  6.   }
  7.   return nr;
  8. }
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