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Mihai_Preda
Jan 25th, 2023
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C++
0.18 KB
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int
f
(
char
s
[
100
]
)
{
int
nr
=
0
, i, n
=
strlen
(
s
)
, p
=
1
;
for
(
i
=
0
;
s
[
i
]
>=
'0'
&&
s
[
i
]
<=
'9'
;
i
++
)
{
nr
=
nr
+
p
*
(
s
[
n
-
i
-
1
]
-
'0'
)
;
p
*
=
10
;
}
return
nr
;
}
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