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MatsGranvik

A new analytic continuation for the Riemann zeta function

Oct 2nd, 2021
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  1. (*start*)
  2. (*Mathematica*)
  3. n = 10^45;
  4. a = 2;
  5. b = 3;
  6. s = 1/2;
  7. N[(a^(s - 1)*Sum[1/k^(s), {k, 1, a*n}] -
  8. b^(s - 1) Sum[1/k^(s), {k, 1, b*n}])/(a^(s - 1) - b^(s - 1)), 20]
  9. N[Zeta[s], 20]
  10. (*end*)
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