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MatsGranvik

Fairly fast formula for Euler Gamma

Aug 14th, 2022
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  1. (*start*)
  2. (*Mathematica*)
  3. r = 6;
  4. c = 7;
  5. digits = 150;
  6. N[HarmonicNumber[c^r] -
  7. Log[c^r] + (-1/2/c^r +
  8. Sum[(-1)^(n + 1)/Denominator[BernoulliB[2 n]/(2 n)]/c^(r*n*2), {n,
  9. 1, r - 1}]), digits]
  10. N[EulerGamma, digits]
  11. %% - %
  12. (*end*)
  13.  
  14. 0.57721566490153286060651209008240243104215933593992359880576723788455\
  15. 0114060141539098461733401449969118294172859999089903125575028248057204\
  16. 188138744400
  17.  
  18. 0.57721566490153286060651209008240243104215933593992359880576723488486\
  19. 7726777664670936947063291746749514631447249807082480960504014486542836\
  20. 224173997645
  21.  
  22. 2.99968238728247686816151467010970321960366272561019200742216507101376\
  23. 151436796396474676*10^-63
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