53_Assign1-7

'''
Name:- Aditya Gangurde
Roll No.:- 53

Assignment No. 1

To calculate salary of employee given his Basic Pay to take as input from user. calculate grass pay. salary of employee let HRA be 10% of Basic Pay TA be 5% of Basic pay let employee pay professional Tax as 2% of total salary. Calculate Net salary payable after deduction

'''

Basic_pay = int(input("Enter basic pay: "))

HRA = Basic_pay*0.1
TA = Basic_pay*0.05
Total_salary = Basic_pay + HRA + TA
P_Tax = Total_salary*0.02
Net_salary = Total_salary - P_Tax

print("HRA is = ",HRA)
print("TA is = ",TA)
print("Total salary is = ",Total_salary)
print("Professional tax = ",P_Tax)
print("Net salary is = ",Net_salary)

'''
output:-

Enter basic pay: 50000
HRA is =  5000.0
TA is =  2500.0
Total salary is =  57500.0
Professional tax =  1150.0
Net salary is =  56350.0

'''
'''
Name:- Aditya Gangurde
Roll no.:- 53

Assignment No. 2

To accept N number from user. Compute and display maximum & minimum list, sum and average of numbers.
'''

sum = 0
list = [1,2,3,4,5,6,7,8,9,10]
for num in list:
    sum = sum +num

average  = sum / len(list)
print ("sum of list element is : ", sum)
print ("Average of list element is ", average )
print ("Maximum is = ",min(list))
print ("Minimum is = ",max(list))



'''
output:-

sum of list element is :  55
Average of list element is  5.5
Maximum is =  1
Minimum is =  10

'''

'''
Name :- Aditya Gangurde
Roll No. :53

Assignment No. 3

To Accept Student's five courses marks and compute his/her result. Student is passing if he/she scores
marks equal to and above 40 in each course. If student scores aggregate greater than 75%,
then the Grade is Distinction. If aggregate is 60>= and <75, then the Grade is First Division.
If aggregate is 50>= and <60, then the Grade is Second Division. If aggregate is 40>= and
<50, then the Grade is Third Division.

'''


List1 = [ ]

for i in range (5):
    a = int(input("Enter Subject Marks: "))
    if (a<40):
        print("Fail!!! ")
        exit()
    List1.append(a)
print ("\n")
print (List1)
print ("\n")

sum = 0
for i in range (5):
    sum = sum + List1[i]
print("Total Marks = ",sum)

percent = 0
percent = float(percent)
percent = sum/5
print("Percentage of Student = ", percent, "%")

if(percent>75):
    print("Grade: Distinction!!!")
elif(percent>=60 and percent<75):
    print("Grade: First Division")
elif(percent>=50 and percent<60):
    print("Grade: Second Division")
elif(percent>=40 and percent<50):
    print("Grade: Third Division")
else:
    print("Fail!!!")


'''
Output:-

Enter Subject Marks: 92
Enter Subject Marks: 87
Enter Subject Marks: 89
Enter Subject Marks: 94
Enter Subject Marks: 98


[92, 87, 89, 94, 98]


Total Marks =  460
Percentage of Student =  92.0 %
Grade: Distinction!!!

'''

'''
Name:-Aditya Gangurde
Roll no.:- 53

Assignment No. 4

To accept a number from user and print digits of a number in a reverse order
'''




def Reverse_Integer(Number):
    Reverse = 0
    while(Number > 0):
        Reminder = Number %10
        Reverse = (Reverse *10) + Reminder
        Number = Number //10
    return Reverse

Number = int(input("Please Enter any Number: "))
Reverse = Reverse_Integer(Number)
print("\n Reverse of entered number is = %d" %Reverse)



'''
output:-
Please Enter any Number: 7264842

Reverse of entered number is = 2484627

'''

'''
Name :- Aditya Gangurde
Rolll No. :- 53

Asssignment No. 5

Write a program in python that accepts a string from user and perform following operations
1. Calculate length of string
2. String reversal
3. Equality cheak of two strings
4. Cheak palindrome
5. Cheak substring

'''
str = input("Enter a string: ")

counter = 0
for s in str:
      counter = counter+1
print("Length of the input string is:", counter)




def reverse(str):
    s = ""
    for ch in str:
        s = ch + s
    return s

print("Given String: ", str)

print("Reversed String: ", reverse(str))




print("Enter 'x' for exit.")
str = input("Enter first string: ")
if str == 'x':
    exit();
else:
    string2 = input("Enter second string: ")
    if str == string2:
        print("\nBoth strings are equal to each other.")
        print(str,"==",string2);
    else:
        print("\nStrings are not equal.")
        print(str,"!=",string2);




def reverse(s):
    return s[::-1]

def isPalindrome(s):
    rev = reverse(s)


    if (s == rev):
        return True
    return False

s = input("Enter the String : ")
ans = isPalindrome(s)

if ans == 1:
    print("Yes")
else:
    print("No")





def check(str, sub_str):
    if (str.find(sub_str) == -1):
        print("NO")
    else:
        print("YES")

sub_str = input("Enter Sub String Which we want to cheak : ")
check(str, sub_str)

'''
Output:-
Enter a string: aditya gangurde
Length of the input string is: 15
Given String:  aditya gangurde
Reversed String:  edrugnag aytida
Enter 'x' for exit.
Enter first string: aditya
Enter second string: aditya

Both strings are equal to each other.
aditya == aditya


'''

'''
Name:- Aditya Gangurde
Roll no.:- 53



Assignment No. 6

To count total characters in file, total words in file, total lines of file and frequency of given word in the file.
'''


searchWord = input("Enter word  to search: ")

with open('File.txt') as infile:
    words = 0
    characters = 0
    count = 0
    for lineno,line  in enumerate(infile,1):
        count = count + line.count(searchWord)
        wordslist = line.split()
        words += len(wordslist)
        characters += sum(len(words) for words in wordslist)


print("total lines are", lineno)
print("total words",words)
print("total characters",characters)
print("frequency is ",searchWord,"is ",count)


""" Output


Enter word  to search: Hello
total lines are 2
total words 8
total characters 35
frequency is  Hello is  1
          """

"""
 Name : Aditya Gangurde
 Roll No. : 53

 Assignment No. 7

Create class EMPLOYEE for storing details (Name,Designation gender, Date of joining and Salary).
 Define function members to compute
 a) total no of employees in organisation
 b) to count of male and female employee
 c) employee with salary more than 10000
 d) employee with designation 'asst manager
"""



class emp():
    count=0
    f_count=0
    m_count=0
    salary_count=0
    desig_count=0
    def __init__(self,name,desig,gender,doj,salary):
        self.name=name
        self.desig=desig
        self.gender=gender
        self.doj=doj
        self.salary=salary
        emp.count+=1
        if(self.gender=="F"):
            emp.f_count+=1
        else:
            emp.m_count+=1
        if(self.salary>10000):
            emp.salary_count+=1
        if(self.desig=="Asst_Manager"):
            emp.desig_count+=1
    def display_emp_count(self):
        print("There are", emp.count,"Employees in office")
    def count_gender(self):
        print("There are", emp.f_count,"female in office")
        print("There are", emp.m_count,"male in office")
    def count_salary(self):
        print("There are", emp.salary_count,"Employees in office having salary>10000")
    def count_desig(self):
        print("There are", emp.desig_count,"Employees in office with designation 'Assistant Manager'")
e1=emp("Nimish","Asst_Manager","M","01-01-2019",10000)
e2=emp("Aditya","Asst_Manager","M","02-02-2019",20000)
e3=emp("Yash","Accountant","F","03-03-2019",30000)
e4=emp("Ayushi","HR","F","04-04-2019",40000)
e5=emp("Amey","Manager","M","05-05-2019",50000)

e5.display_emp_count()
e5.count_gender()
e5.count_salary()
e5.count_desig()

"""
output:

There are 5 Employees in office
There are 2 female in office
There are 3 male in office
There are 4 Employees in office having salary>10000
There are 2 Employees in office with designation 'Assistant Manager'

"""