Palindrome finder using python 3

"""
Call functon 'f' with numerical a numerical argument 't'.  The program will run for 't' seconds and output any palindromic numbers it calculates.
Created by MRH3ADSH0T
"""
from timeit import default_timer as dt

def f(t):
    x=0
    st=dt()
    while (dt()-st<=t):
        if (str(x)[::-1] == str(x)):
            print("Palindrome: "+str(x))
        else:
            #print(x)
            pass
        x+=1


f(2.5)