Ryspekov's Fibonacci sequence formula PYTHON

def zn(x):
    x=abs(x)
    x+=4
    x=x//5
    x=pow(2,x)%2
    return x

b=int(input());
b=b-1
x=1
n=2
while(n<b):
    n=n+1
    k=int(x*(1+pow(5,0.5))/2);
    x=k+zn(n%3)*(k%2)+(1-zn(n%3))*zn(k%2);
    print(x);
else:
 print()
n=n+1
x=x-zn(b)
print(x)