#!/bin/bash
# produce dd/mm/yyyy date, other formats possible
date=$(date +"%d/%m/%Y")
# see https://stackoverflow.com/questions/407523/escape-a-string-for-a-sed-replace-pattern
escaped_date=$(echo "$date" | sed 's/[/&]/\&/g')
sed -i 's/$(date)/'"$escaped_date"'/g' "$*"