import Foundation
import UIKit


// these are the "parts" we want to extract from the string
var calendarName = ""
var dateTimeParts = ""
var locationName = ""

var index = -1

var str = "Today 11:55 AM Tony plays pickleball weekly on court 1 calendar Tony repeating weekly location court 1"

var wordArrOriginal = str.components(separatedBy: " ")      // "original" array without change to lower-case
var wordArrTrimmed = str.lowercased().components(separatedBy: " ")

print(#line, "wordArrayOriginal:", wordArrOriginal)
print(#line, "wordArrayTrimmed: ", wordArrTrimmed)

print() // print a blank line


// now let's look for Repeating
// if we find it, we want to get the NEXT word as the repeating frequency name, and remove it plus the precending "repeat" keyword from BOTH arrays

//index = wordArrTrimmed.index(of: "repeating") ?? -1

if index == -1 {
    index = wordArrTrimmed.index(of: "repeat") ?? -1
} else if index == -1 {
    index = wordArrTrimmed.index(of: "repeating") ?? -1
} else if index == -1  {
    index = wordArrTrimmed.index(of: "reoccurring") ?? -1
}

print(#line, "index of location:", index)

print()

print(#line, "wordArrTrimmed.count:", wordArrTrimmed.count)


if index > -1 {     // we found a repeating type word

    if index < wordArrTrimmed.count - 1 {   // this tells us there is at least 1 more word after "repeat"

        // so, assign the rest of the string (the rest of the array elements) to our locationName var

        locationName = wordArrOriginal[(index + 1)..<wordArrOriginal.count].joined(separator: " ")

        // and remove those words (plus the "repeat" keyword) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    } else {    // "Repeat" was the LAST word, so just remove "Location" (the last element) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    }

} // end if repeat type word was found


// let's look for Calendar
// if we find it, we want to get the NEXT word as the calendar name, and remove it plus the precending "calendar" keyword from BOTH arrays

index = wordArrTrimmed.index(of: "calendar") ?? -1

print(#line, "index of calendar:", index)

print()

if index > -1 {     // we found the word "calendar"

    if index < wordArrTrimmed.count - 1 {   // this tells us there is at least 1 more word after "calendar"

        // so, assign the NEXT word to our calendarName var

        calendarName = wordArrOriginal[index + 1]

        // and remove that word (plus the precending "calendar" keyword) from BOTH arrays

        wordArrOriginal.removeSubrange(index...index + 1)
        wordArrTrimmed.removeSubrange(index...index + 1)

    } else {    // "Calendar" was the LAST word, so just remove "Calendar" (the last element) from BOTH arrays

        wordArrOriginal.remove(at: index)
        wordArrTrimmed.remove(at: index)

    }

} // end if "calendar" was found

print(#line, "wordArrayOriginal:", wordArrOriginal)
print(#line, "wordArrayTrimmed: ", wordArrTrimmed)

print()


// now let's look for Location
// if we find it, we want to get the REST of the string as the location name, and remove that word (those words) plus the precending "location" keyword) from BOTH arrays

index = wordArrTrimmed.index(of: "location") ?? -1

print(#line, "index of location:", index)

print(#line, "wordArrTrimmed.count:", wordArrTrimmed.count)


print()

if index > -1 {     // we found the word "location"

    if index < wordArrTrimmed.count - 1 {   // this tells us there is at least 1 more word after "location"

        // so, assign the rest of the string (the rest of the array elements) to our locationName var

        locationName = wordArrOriginal[(index + 1)..<wordArrOriginal.count].joined(separator: " ")

        // and remove those words (plus the "location" keyword) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    } else {    // "Location" was the LAST word, so just remove "Location" (the last element) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    }

} // end if "location" was found


// now let's look for Repeating
// if we find it, we want to get the NEXT word as the repeating frequency name, and remove it plus the precending "repeat" keyword from BOTH arrays

if index == -1 {
    index = wordArrTrimmed.index(of: "repeat") ?? -1
} else if index == -1 {
    index = wordArrTrimmed.index(of: "repeating") ?? -1
} else if index == -1  {
    index = wordArrTrimmed.index(of: "reoccurring") ?? -1
}

print(#line, "index of location:", index)

print()

print(#line, "wordArrTrimmed.count:", wordArrTrimmed.count)


if index > -1 {     // we found a repeating type word

    if index < wordArrTrimmed.count - 1 {   // this tells us there is at least 1 more word after "repeat"

        // so, assign the rest of the string (the rest of the array elements) to our locationName var

        locationName = wordArrOriginal[(index + 1)..<wordArrOriginal.count].joined(separator: " ")

        // and remove those words (plus the "repeat" keyword) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    } else {    // "Repeat" was the LAST word, so just remove "Location" (the last element) from the array

        wordArrOriginal.removeSubrange(index..<wordArrOriginal.count)
        wordArrTrimmed.removeSubrange(index..<wordArrTrimmed.count)

    }

} // end if repeat type word was found


print(#line, "wordArrayOriginal:", wordArrOriginal)
print(#line, "wordArrayTrimmed: ", wordArrTrimmed)

print()

print(#line, "calendarName:", calendarName)
print(#line, "locationName:", locationName)