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Jul 19th, 2018
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PHP 0.35 KB | None | 0 0
  1. <?php
  2. $sql = "SELECT * FROM news WHERE id=1";
  3.             $result = mysql_query($sql);
  4.             $row = mysql_fetch_array($result);
  5. $beginyear = mysql_query("SELECT YEAR(begindate) AS beginyear FROM news WHERE id=1");
  6. $row = mysql_fetch_assoc($beginyear);
  7. ?>
  8. <form method="post" action="">
  9.     <input name="beginjaar" value="<?php echo $row['beginyear']; ?>" />
  10. </form>
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