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Oct 21st, 2017
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MySQL 0.22 KB | None | 0 0
  1. #1
  2. (SELECT COUNT(t.ticket_id) FROM tickets AS t
  3.     GROUP BY t.flight_id
  4.     HAVING OLD.flight_id = t.flight_id)    - Ne minava 1 test
  5.  
  6. #2
  7. (SELECT COUNT(t.ticket_id) FROM tickets AS t
  8. WHERE t.flight_id=OLD.flight_id)  -Minava
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