S01E01

#include<iostream>

#define long long long
#define nln '\n'

using namespace std;

int main()
{
    long t;
    cin >> t;
    for (long i = 1; i <= t; ++i)
    {
        long n;
        cin >> n;
        if (n >= 21)
            cout << "yes" << nln;
        else
            cout << "no" << nln;
    }
    return 0;
}