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Farz0l1x
Mar 5th, 2024
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Python
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def
f
(
n
)
:
s
=
''
while
n
>
0
:
s +
=
str
(
n %
5
)
n //
=
5
s
=
s
[
::-
1
]
return
s
n
=
5
**
2004
-
5
**
1016
-
25
**
508
-
5
**
400
+
25
**
250
-
27
b
=
f
(
n
)
print
(
b.
count
(
'4'
)
)
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