8 задание

def toOct(n):
    tempStr = ""
    while n > 0:
        tempStr += str(n % 8)
        n //= 8

    outStr = tempStr[::-1]
    return outStr

def checkNumber(strNumber):
    for i in range(0, 10):
        if strNumber.count(str(i)):
            return False
    for i in range(0, len(strNumber) - 3):
        if int(strNumber[i]) % 2 == 0 and int(strNumber[i + 1]) % 2 == 0 and int(strNumber[i + 2]) % 2 == 1 and int(strNumber[i + 3]) % 2 == 1:
            return False
        if int(strNumber[i]) % 2 == 1 and int(strNumber[i + 1]) % 2 == 1 and int(strNumber[i + 2]) % 2 == 0 and int(strNumber[i + 3]) % 2 == 0:
            return False
#print(toOct(999999))
score = 0
for i in range(262144, 2097151):
    if checkNumber(toOct(i)):
        score += 1

print(score)