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Donald_Fortier

Untitled

May 28th, 2015
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  1. #include <iostream>
  2. #include <cmath>
  3. using namespace std;
  4.  
  5. void printArea(double coord[]);
  6.  
  7. int main()
  8. {
  9.  
  10.     cout << "Enter the coordinates of six points: \n";
  11.     double coord[12];
  12.     cin >> coord[12];
  13.    
  14.  
  15.     cout << "The total area is ";
  16.     printArea(coord);
  17.  
  18.     return 0;
  19. }
  20.  
  21.  
  22.     void printArea(double coord[])
  23.     {
  24.         double D[9];
  25.  
  26.         D[0] = sqrt(pow(coord[0] - coord[2], 2) + pow(coord[1] - coord[3], 2));
  27.         D[1] = sqrt(pow(coord[2] - coord[4], 2) + pow(coord[3] - coord[5], 2));
  28.         D[2] = sqrt(pow(coord[0] - coord[4], 2) + pow(coord[1] - coord[5], 2));
  29.         D[3] = sqrt(pow(coord[4] - coord[6], 2) + pow(coord[5] - coord[7], 2));
  30.         D[4] = sqrt(pow(coord[0] - coord[6], 2) + pow(coord[1] - coord[7], 2));
  31.         D[5] = sqrt(pow(coord[6] - coord[8], 2) + pow(coord[7] - coord[9], 2));
  32.         D[6] = sqrt(pow(coord[0] - coord[8], 2) + pow(coord[1] - coord[9], 2));
  33.         D[7] = sqrt(pow(coord[8] - coord[10], 2) + pow(coord[9] - coord[11], 2));
  34.         D[8] = sqrt(pow(coord[0] - coord[10], 2) + pow(coord[1] - coord[11], 2));
  35. /* Can you figure out a way to do this in a loop? */
  36.  
  37.         double S[4];
  38.         S[0] = (D[0] + D[1] + D[2]) / 2;
  39.         S[1] = (D[2] + D[3] + D[4]) / 2;
  40.         S[2] = (D[4] + D[5] + D[6]) / 2;
  41.         S[3] = (D[6] + D[7] + D[8]) / 2;
  42. /* Can you figure out a way to do this in a loop? */
  43.  
  44.         double A[4];
  45.         A[0] = sqrt(S[0] * (S[0] - D[0]) * (S[0] - D[1]) * (S[0] - D[2]));
  46.         A[1] = sqrt(S[1] * (S[1] - D[2]) * (S[1] - D[3]) * (S[1] - D[4]));
  47.         A[2] = sqrt(S[2] * (S[2] - D[4]) * (S[2] - D[5]) * (S[2] - D[6]));
  48.         A[3] = sqrt(S[3] * (S[3] - D[6]) * (S[3] - D[7]) * (S[3] - D[8]));
  49. /* Can you figure out a way to do this in a loop? */
  50.  
  51.         double TotalArea = 0;
  52.         for (int i = 0; i < 4; i++)
  53.         {
  54.             TotalArea += A[i];
  55.         }
  56.         cout << TotalArea << endl;
  57.  
  58.     }
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