#### Scenario 1
**Inputs:**
* Target number: 20
* Number to get multiples: [3, 5]

**Output**
* 78
---
Algorithm
1. Create an empty array, called `multiples`, that will contain the list of multiples

   `multiples = []`
2. Check if there are numbers to get multiples from. If there are none set it to [3, 5]

   Retains inputs since there are numbers to get multiples from.
3. Loop over the list of numbers to get multiples from

   `[3, 5]`
   1. For every `number`, set the value of `current_number` to `number` to keep track of the incremented value.

      `current_number = 3`; `current_number = 5`
   2. Increment `current_number` by `number` while the value is less than the target number

      `while current_number < 20; current_number = current_number + number`
      1. Before every increment, add `current_number` to `multiples`

         `multiples = [3]; multiples = [3, 6]; mutliples = [3, 6, 9] ...`

         `... multiples = [3, 6, 9, 12, 15, 18, 5, 10, 15]`
4. Filter out the duplicate numbers from `multiples`

   `multiples = [3, 6, 9, 12, 15, 18, 5, 10]`
5. Return the sum of the numbers in `multiples`

   `78`