found some old chemistry homework

2.3)

Natriumnitrat NaNO₃ dekomponerer til NaNO₂ og O₂ ved oppvarming fucking details who gives a flying fuck
Hvor mange gram NaNO₂ ble dannet når dekomponeringen av NaNO₃ gav 5.29g O₂?

Balanserer likning:
         NaNO₃ -> NaNO₂ + O₂
[!]---  2NaNO₃ -> 2NaNO₂ + O₂  ---[!]
₀2Na + 2N + 6O -> 2Na + 2N + 4O + 4O
₀2Na + 2N + 6O -> 2Na + 2N + 6O

[Na] 22.990
 [N] 14.007
 [O] 15.999

2NaNO₃ -> 2NaNO₂ + O₂
temporal weight constants
2NaNO₃ == 2( 22.990+14.007+3(15.999) ) == 2(36,997+3(15.999)) == 84,994
2NaNO₂ == 2( 22.990+14.007+2(15.999) ) == 2(36,997+2(15.999)) == 68,995
    O₂ == 2(15.999)                    == 31,998

n = x / F_u = whatever
n = 5.29 / 31.998 = 0,1653228326770423
2NaNO₂g = n(68,995) = 11,41g

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