Advertisement
fsimen

euler1

May 25th, 2014
165
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
  1. -- If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of  these multiples is 23.
  2. -- Find the sum of all the multiples of 3 or 5 below 1000.
  3.  
  4. foldr1 (+) [c | c <- [1..1000], ((c `mod` 3) == 0) && ((c `mod` 5) == 0)]
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement