function findMin(){
    let A = [1, 4, 5, 8, 10];
    let B = [6, 1, 15];
    let C = [2, 3, 6, 6];
    let minValue = Number.MAX_VALUE;

    for (i = 0; i < A.length; i++) {
        for (j = 0; j < B.length; j++){
            for (k = 0; k < C.length; k++){
                let currValue = Math.abs(Math.max(A[i],B[j], C[k]) - Math.min(A[i],B[j], C[k]));
                if (currValue < minValue)
                {
                    minValue = currValue;
                }
            }
        }
}
    return minValue;
}


print(findMin());