- def hours_difference(time_1, time_2):
- '''(float, float) -> float
- Return the number of hours later that a time in seconds
- time_2 is than a time in seconds time_1.
- >>> hours_difference(1800.0, 3600.0)
- 0.5
- >>> hours_difference(3600.0, 1800.0)
- -0.5
- >>> hours_difference(1800.0, 2160.0)
- 0.1
- >>> hours_difference(1800.0, 1800.0)
- 0.0
- '''
- return(round((time_2/3600) - (time_1/3600) ,1))
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Oct 9th, 2012
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