from re import compile as compile_pattern


filename = "morgue.txt"
with open(filename, "r", encoding="utf-8", errors="ignore") as file_handle:
    lines = file_handle.readlines()

## lines now contains a list of all the text lines in the morgue file
print(lines[0]) # prints the first line of the file: "Dungeon Crawl Stone [..]" Can be used to grab version
print(lines[4]) # prints the 5th line (start counting at 0) of the file, can get the score, name, title, level and current hps

# go over all lines in the "lines" variable
for line in lines: # store current line in the "line" variable

    # Lets find out how much gold, we know that around line 17 the line contains the gold amount, so lets look for it
    if "Gold:" in line: # the text "Gold:" is mentioned in the morgue
        print(line) # Can remove this test/debuggin by adding # at the start

        # So lets grab all the digits after "Gold: ". We do not know how many, so let's use regex
        # First we define a pattern:
        #    1. Look for the text 'Gold: '
        #    2. '()' means to capture what is inside into a group, means we want to grab this
        #    3. '\d' means to look for digits (i.e. 0-9) and '+' means at least one, but grab all
        pattern = compile_pattern('Gold: (\d+)')
        # Apply the pattern search on the line we know as "Gold: " in it and store the result in 'match'
        match = pattern.match(line)
        if not match: # in case of bug, catch no match
            print("Error, no gold found on ", line)
            exit(1) # We have a bug, lets just quit and fix it
        # grab the gold amount that we stored the first group
        gold = match.group(1)
        print("This character had ", gold, " gold") # just print the gold since we don't have anything fancy to do with it for now!