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Mar 17th, 2016
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  1. private void button1_Click(object sender, EventArgs e)
  2. {
  3. using (MySqlConnection con = new MySqlConnection("server=xxxx;user=xxxx;database=xxxx;password=xxxx;"))
  4. {
  5. try
  6. {
  7. con.Open();
  8. MessageBox.Show("Подключился");
  9. }
  10. catch (Exception ex)
  11. {
  12. MessageBox.Show(ex.Message);
  13. }
  14. }
  15. }
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