Simple Homophonic Encrypt

from random import randint
mykey = {
"A":[1,2,3,4,5],
"B":[11,12,13,14,15],
"C":[21,22,23],
"D":[31,32,33],
"E":[41,42,43],
"F":[51,52,53],
"G":[61,62,63],
"H":[71,72,73],
"I":[81,82,83],
"J":[91,92,93],
"K":[101,102,103],
"L":[111,112,113],
"M":[121,122,123],
"N":[131,132,133],
"O":[141,142,143],
"P":[151,152,153],
"Q":[161,162,163],
"R":[171,172,173],
"S":[181,182,183],
"T":[191,192,193],
"U":[201,202,203],
"V":[211,212,213],
"W":[221,222,223],
"X":[231,232,233],
"Y":[241,242,243],
"Z":[251,252,253]
}
word = raw_input("Input some Text : ").upper()
cipher = [mykey[char][randint(0, len(mykey[char])-1)] for char in word]
print "Cipher Text [%s] is = %s"%(word,cipher)

"""
*****Debug Mode******
$ python homo_poc.py
Input some Text : homophonic
H => 73
O => 142
M => 122
O => 143
P => 151
H => 73
O => 142
N => 131
I => 81
C => 21
Cipher Text is = [73, 142, 122, 143, 151, 73, 142, 131, 81, 21]
"""