Array items appeared only once in JS

// Write a function which will take an array as a parameter and will return only the numbers that are repeated once.
// Eg: sample array [1, 2, 2, -4, 3, 1, -3, 4, 4, 1, 5, -4],
// output: -3, 3, 5

const array = [1, 2, 2, -4, 3, 1, -3, 4, 4, 1, 5, -4]

const max = Math.max(...array)

const min = Math.min(...array)

const positive_counts = []

const negative_counts = []

const answers = []

for (let i = 0; i <= max; i++) {
    positive_counts[i] = 0
}

for (let i = 0; i <= (-1 * min); i++) {
    negative_counts[i] = 0
}

for (let i = 0; i < array.length; i++) {
    if (array[i] >= 0) {
        positive_counts[array[i]]++
    } else {
        negative_counts[(-1 * array[i])]++
    }
}

for (let i = 0; i < negative_counts.length; i++) {
    if (negative_counts[i] == 1) {
        answers.push((-1 * i))
    }
}

for (let i = 0; i < positive_counts.length; i++) {
    if (positive_counts[i] == 1) {
        answers.push(i)
    }
}

console.log(answers)