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Jul 20th, 2018
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  1. from u in Users
  2. join l in Languages on u.LanguageId equals l.Id
  3. group u by l.Name into g
  4. orderby g.Count() descending
  5. select new { Id = l.Id, NameAndCount = g.Key + " (" + g.Count() + ")" }
  6.  
  7. from u in Users
  8. join l in Languages on u.LanguageId equals l.Id
  9. group l by l.Id into g
  10. orderby g.Count() descending
  11. select new { Id = g.Key, NameAndCount = g.First().Name + " (" + g.Count() + ")" }
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