Advertisement
Guest User

Untitled

a guest
Jan 15th, 2018
147
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 0.61 KB | None | 0 0
  1. CCFE4-TVYTE-CGIFK
  2.  
  3. AAAAA = CCFE4
  4. - Put "5183803" into Wolfram Alpha and get that two prime factors are 73 & 71011.
  5. - "What number has prime factors of 2, 73, 71011 (and has 12 divisors)"
  6. - Adding more than one power to any of the numbers creates something too big to convert into a a 5-character string
  7. - 2^2 * 73 * 71011 = 20,735,212 which has 12 divisors
  8. - Convert that do base36 and get CCFE4
  9.  
  10. BBBBB = TVYTE
  11. - Wrote some code to count up how many times each string appeared
  12. - Sorted it
  13. - Took the 124th
  14.  
  15. CCCCC = CGIFK
  16. - Wrote some code to brute force the hash
  17. - Keep trying all options till it matches
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement