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bobhig

Sequential searches

Feb 12th, 2019
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Python 0.85 KB | None | 0 0
  1. # sequential search on random list
  2. # returns first position of item in list
  3. # returns none if item is not in list
  4. # Search2 improves efficiency on a sorted list by stopping once > passed item
  5.  
  6. import random
  7.  
  8. random_items = []
  9.  
  10. def search(alist, item): #returns first position of item in a list
  11.     for position, value in enumerate(alist,1):
  12.         if value == item:
  13.             return(value, position)
  14.  
  15. def search_2(alist, item):
  16.     for position, value in enumerate(alist,1):
  17.         if item == value:
  18.             return(value,position)
  19.         elif item < value:
  20.             return("item is not in list")
  21.  
  22. # populate list
  23. for x in range (0, 30):
  24.     random_items.append(random.randint(0, 30))
  25.  
  26. print(random_items)
  27.  
  28. sorted_items = sorted(random_items)
  29. print(sorted_items)
  30.  
  31. print(search(random_items, 14))
  32. print(search_2(sorted_items, 14))
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