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Dec 16th, 2017
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  1. void stepen(int* cv, int* cv2,int* y) {
  2. int u = 0, k = 0, j = 0, i = 0,cr=0,v=0,t=0;
  3.  
  4. cr = 0;
  5. for (i = 1; i <= cv[0]; i++) {
  6.  
  7. for (j = 1; j <= cv2[0]; j++) {
  8. cr = cv[i] * cv2[j];
  9. k = i + j - 1;
  10. while (cr > 0) {
  11. cr = cr + y[k];
  12. y[k] = cr % 10;
  13. cr = cr / 10;
  14. if (k > y[0]) y[0] = k;
  15. k = k + 1;
  16. }
  17.  
  18. }
  19.  
  20. }
  21. }
  22.  
  23. case'^': {
  24. int n = 0;
  25. int cv[N+5];
  26. int cv2[N+5];
  27.  
  28. printf("Enter the first number ");
  29. readlong(a);
  30. printf("nEnter the stepen ");
  31. scanf_s("%d", &n);
  32. for (i = 0; i < N+5; i++) {
  33. cv[i] = a[i];
  34. cv2[i] = a[i];
  35. }
  36. for (t = 0; t < n-1; t++) {
  37. stepen(cv, cv2, y);
  38. for (zxc = 0; zxc < N + 5; zxc++) {
  39. cv2[zxc] = 0;
  40. cv2[zxc] = y[zxc];
  41. }
  42. }
  43. writelong(y);
  44.  
  45. break;
  46. }
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