a_x = 1
    b_x = (-2 * point[0])                   # point[0] = x-coordinate of point
    c_x = point[0]**2 + point[1]**2 - C**2  # point[1] = y-coordinate of point
    d_x = (b_x**2) - (4 * a_x * c_x)
    sqr_d_x = cmath.sqrt(d_x)               # Takes the square root of d_x

    x_1 = (-b_x - sqr_d_x)/(2 * a_x)        #Sol 1,x-coordinate of base vertice
    x_2 = (-b_x + sqr_d_x)/(2 * a_x)        #Sol 2,x-coordinate of base vertice

    Pw_x = min(x_1,x_2)              # Since isosceles triangle is slanted on 2D space
    Pz_x = max(x_1,x_2)

    a_y = 1
    b_y = (-2 * point[1])
    c_y = point[0]**2 + point[1]**2 - C**2
    d_y = (b_y**2) - (4 * a_y * c_y)
    sqr_d_y = cmath.sqrt(d_y)

    y_1 = (-b_y - sqr_d_y)/(2 * a_y)
    y_2 = (-b_y + sqr_d_y)/(2 * a_y)

    Pw_y = max(y_1,y_2)
    Pz_y = min(y_1,y_2)

    Pw = (Pw_x,Pw_y)         # left base vertice
    Pz = (Pz_x,Pz_y)         # right base vertice

    print(cmath.sqrt((point[0] - Pw_x)**2 + (point[1] - Pw_y)**2))
    print(cmath.sqrt((point[0] - Pz_x)**2 + (point[1] - Pz_y)**2))