#include <iostream>
#include <cmath>
#include <iomanip>

using namespace std;

// Function prototype (declaration)
int add(int, int);
double doubleadd(double, double);
float squareroot(float);

int main()
{
	int bignum = 2147483646;

	//1. Show that for unsigned int a,b and a>0, b>0, we can get a+b < a
	//2. Show that for int a,b and a>0, b>0, we can get a+b < 0
    cout << "Two positive numbers added = ";
    int num = add(bignum , 2  );
    cout << num << endl;

    //3. Show that for int a,b and a<0, b<0, we can get a+b > 0
    int bignegnum = bignum * -1;
    int num2 = add(bignegnum , -10);
    cout << "Two negative numbers added = " << num2 << endl;

    //4. Show that for double x and x>0 we can get 1. + x = = 1.
    double dnum1 = 1.0;
    double dnum2 = .00000000000000000001;
    dnum1 = doubleadd(dnum1, dnum2);
    cout << "Two double numbers added = " << dnum1 << endl;

    //5. Show that for double a,b,c in some cases (a+b)+c != (c+b)+a
    dnum1 = 2000000;
    dnum2 = 1e20;
   	double dnum3 = -1e20;
    double dnum4 = (dnum1 + dnum2) + dnum3;
    double dnum5 = (dnum3 + dnum2) + dnum1;
    cout<< "The two different numbers when added in different order: " << dnum4  << " and " << dnum5 <<endl;

    //6. Show the results of the following power function: pow(-2., 3), pow(-2., 3.0) , pow(-2., 3.00000000001)
    double powBase = -2.;
    double powExp = 3;
    double powNum = pow(powBase, powExp);
    cout << " Pow(-2.3,3) = " << powNum << endl;

    powExp = 3.0;
    powNum = pow(powBase, powExp);
    cout << " Pow(-2.,3.0) = " <<powNum << endl;

    powExp = 3.00000000001;
    powNum = pow(powBase, powExp);
    cout << " Pow(-2.,3.00000000001) = " <<powNum << endl;

    //7. Show the memory size of the following constants 1. , 1.F, 1 , '1' , and "1"
    cout<<"Size of (1.) : " <<sizeof(1.)<< endl;
    cout<<"Size of (1.F) : "<<sizeof(1.F) << endl;
    cout<<"Size of (1) : "<<sizeof(1)<< endl;
    cout<<"Size of ('1') : "<<sizeof('1')<< endl;
    cout<<"Size of (\"1\") : "<<sizeof("1")<< endl;

    //8. Display 1./3. using 20 digits and show the correct and incorrect digits
    cout<<"1./3: " << setprecision(20) << 1./3 <<endl;

    /* 9. Display all printable characters of the ASCII table in 3 columns:
	first column: 32-63, second column: 64-95, third column: 96-127. Each column
	must include the numeric value and the corresponding character. Following is
	an example of one of 32 rows in the ASCII table:
	33 ! 65 A 97 a */

	for (int i = 32; i< 63; i++){
		cout << i << " " << (char)i <<"\t" << (i+32) <<" " << (char)(i+32) << "\t" << (i+64) << " " << (char)(i+64) <<endl;
	}

	//10. Compute sqrt(2.) using your own program for square root function.
	cout<< "Square root of (2.) is " << squareroot(2);

    return 0;
}


int add(int a, int b)
{
    int sum;
    sum = a + b;
    return sum;
}


double doubleadd(double a, double b){

	double sum;
	sum = a + b;
	return sum;
}

float squareroot(float a)

{
    float root = a/2.0;
    float temp = 0;

    while (root != temp)
    {
        temp = root;
        root = ( a / temp + temp) / 2;
    }
    return root;
}