Ledger Nano X - The secure hardware wallet
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remainder fact

a guest Mar 30th, 2020 89 Never
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  1. t = int(input())
  2.  
  3. li=[]
  4. for i in range(t):
  5.     a=int(input())
  6.     li.append(a)
  7.  
  8. a= sorted(li)[-1]
  9.  
  10. d=0
  11.  
  12. for i in range(2,a+1):
  13.     c=0
  14.     for k in range(1,t):
  15.         if li[k]%i==li[k-1]%i:
  16.             c+=1
  17.             #print(c)
  18.     if c==(t-1):
  19.         print(i,end=" ")
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