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Jan 22nd, 2018
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  1. #!/bin/bash
  2. for i in `ls -t *xml|awk 'BEGIN{FS="_"}{if (++dup[$1] >= 2) print}'`;
  3. do
  4. rm $i
  5. done
  6.  
  7. AECZ00205_010917_1506689024063.xml
  8. AECZ00205_010917_1506689024064.xml
  9. AECZ00205_010917_1506689024066.xml
  10. AECZ00207_010917_1506690865368.xml
  11. AECZ00207_010917_1506690865369.xml
  12. AECZ00207_010917_1506690865364.xml
  13. AECZ00209_010917_1506707811518.xml
  14. AECZ00209_010917_1506707811519.xml
  15. AECZ00209_010917_1506707811529.xml
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