решение системы с заданием. 12 вариант

////вариант 12
//      |a*i*i*i + b*i*i + c;
// F = < (i - a) / (i - c);
//      |i / c + i / a;
// если ((int(a) || int(b) && int(c)) != 0) вывести не int, иначе int



#include <iostream>
#include <conio.h>
#include <cmath>
#include <iomanip>
#include <stdio.h>


using namespace std;


int main(){

    float a, b, c, r, Xnach, Xkon, Xd;


    cout << "vvod a = ";
    cin >> a;
    cout << "vvod b = ";
    cin >> b;
    cout << "vvod c = ";
    cin >> c;
    cout << "vvod Xnach = ";
    cin >> Xnach;
    cout << "vvod Xkon = ";
    cin >> Xkon;
    cout << "vvod Xd = ";
    cin >> Xd;
    cout << "___________________"<<  endl;
    cout << "|  x     |   F    |" << endl;
    cout << "|________|________|" << endl;


    cout.setf(ios::fixed);
    cout << setprecision(1);


    for (float i = Xnach; i < Xkon; i += Xd){

        if (i < 0.6 && b + c != 0)
            r = a*i*i*i + b*i*i + c;


        else if (i > 0.6 && b + c == 0){
            if (i - c >= 0)
                r = (i - a) / (i - c);
        }

        else  if (c != 0 && a != 0)
            r = i / c + i / a;
        else continue;
        cout.width(4);

        if ((int(a) || int(b) && int(c)) != 0){

            printf_s("| %5.1f  | %5.1f  |\n", i,r );
        }
        else printf_s("| %5.1f  | %5.1f  |\n"), i, int(r);
        cout << endl;



    }

    cout << "-------------------" << endl;



    _getch();
    return 0;
}