Operator precedence

//operator precedence exercise (use the debugger)
int main() {
    float x = 3;
    float a = x*x / 4 + 1;
    float b = (x*x) / 4 + 1; //these three are all the same
    float c = ((x*x) / 4) + 1; //but I think this is clearer
    a = 2.0f;
    b = 1.0f;
    c = 3.0f;
    float result1 = a / b * c; //ambiguous (in mathematics)
    float result2 = (a / b)*c; //this is how C++ evaluates it
    float result3 = a / (b*c); //we can change the order using parenthesis
    return 0;
}