Return address modification

//This is what I learnt today.
//Credits: http://stackoverflow.com/questions/10264512/asssembly-base-pointer-and-stack-pointer
#include <Windows.h>
#include <iostream>

int inc = 0;
int timesrun = 555;
/*
What it looks like after the stack frame is setup
+-------------+
| Parameter 2 | <-- [ebp + 12]
+-------------+
| Parameter 1 | <-- [ebp + 8]
+-------------+
| Return Addr | <-- [ebp + 4]
+-------------+
| saved ebp   | <-- ebp
+-------------+ <-- esp
*/
void twoargs()
{
    void* basePtr;
    __asm mov basePtr, ebp;
    /*If you make this a pointer and dereference it, it'll make int main() run |timesrun| amount of times*/
    DWORD* retnaddr = (DWORD*)((DWORD)basePtr+ 0x4); //Return address of twoargs()
    //Example: DWORD* retnaddr = (DWORD*)(*(DWORD*)basePtr+ 0x4); // Return address of main()
    if (timesrun > 1)
    {
        timesrun -= 1;
        *retnaddr -= 0x5; //Move it back to ebp - 0x1
    }
    inc++;
}

int main()
{
    int expected = timesrun;
    twoargs();
    printf("%i\nexpected output: %i", inc, expected);
    getchar();
    return 0;
}