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Jun 24th, 2017
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  1. #include <bits/stdc++.h>
  2.  
  3. using namespace std;
  4.  
  5. #define FOR(i, j, k) for(int i = j; i < k; ++i)
  6. #define rep(i, j) FOR(i, 0, j)
  7. #define FORr(i, j, k) for(int i = j; i >= k; --i)
  8. #define repr(i, j) FOR(i, j, 0)
  9. #define INF (1 << 30)
  10.  
  11. typedef long long ll;
  12. typedef unsigned long long ull;
  13. typedef pair<int, int> P;
  14. typedef pair<P, int> Pi;
  15.  
  16. const int MOD = 1e9 + 7;
  17. const int dy[]={0, 0, 1, -1};
  18. const int dx[]={1, -1, 0, 0};
  19.  
  20. template <class T> void chmin(T& a, const T& b) { a = min(a, b); }
  21. template <class T> void chmax(T& a, const T& b) { a = max(a, b); }
  22.  
  23. struct edge { int u, v, cost; };
  24.  
  25. bool comp(const edge& e1, const edge& e2) {
  26. return e1.cost < e2.cost;
  27. }
  28.  
  29. int N;
  30. vector<P> vx, vy;
  31. vector<edge> es;
  32. int par[100001], rk[100001];
  33. ll res = 0;
  34.  
  35. void init(int n) {
  36. rep(i, n) {
  37. par[i] = i;
  38. rk[i] = 0;
  39. }
  40. }
  41.  
  42. int find(int x) {
  43. if(par[x] == x) return x;
  44. else return par[x] = find(par[x]);
  45. }
  46.  
  47. void unite(int x, int y) {
  48. x = find(x);
  49. y = find(y);
  50. if(x == y) return;
  51.  
  52. if(rk[x] < rk[y]) par[x] = y;
  53. else par[y] = x;
  54. if(rk[x] == rk[y]) ++rk[x];
  55. }
  56.  
  57. bool same(int x, int y) {
  58. return find(x) == find(y);
  59. }
  60.  
  61. void kruskal() {
  62. sort(es.begin(), es.end(), comp);
  63. init(N);
  64. rep(i, es.size()) {
  65. edge e = es[i];
  66. if(!same(e.u, e.v)) {
  67. unite(e.u, e.v);
  68. res += e.cost;
  69. }
  70. }
  71. }
  72.  
  73. int main() {
  74. scanf("%d", &N);
  75. rep(i, N) {
  76. int X, Y;
  77. scanf("%d %d", &X, &Y);
  78. vx.push_back(P(X, i)); vy.push_back(P(Y, i));
  79. }
  80. sort(vx.begin(), vx.end()); sort(vy.begin(), vy.end());
  81. FOR(i, 1, vx.size()) {
  82. es.push_back({vx[i - 1].second, vx[i].second, vx[i].first - vx[i - 1].first});
  83. }
  84. FOR(i, 1, vy.size()) {
  85. es.push_back({vy[i - 1].second, vy[i].second, vy[i].first - vy[i - 1].first});
  86. }
  87. kruskal();
  88. printf("%lld\n", res);
  89. return 0;
  90. }
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