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danchaofan

Euler #71

Dec 8th, 2017
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Python 0.25 KB | None | 0 0
  1. best, num = 0, 0
  2. for a in range(2, 10**6+1):
  3.     print(a)
  4.     index = int(3*a/7) - 1
  5.     for b in range(index, a):
  6.         if (3/7) > (b/a) > best:
  7.             best = b/a
  8.             num = b
  9.         if (3/7) < (b/a):
  10.             break
  11. print(num)
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