Python - easy way to add N seconds to a datetime.time?

>>> datetime.time(11, 34, 59) + 3
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'int'
>>> datetime.time(11, 34, 59) + datetime.timedelta(0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
>>> datetime.time(11, 34, 59) + datetime.time(0, 0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.time'

def add_secs_to_time(timeval, secs_to_add):
    secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
    secs += secs_to_add
    return datetime.time(secs // 3600, (secs % 3600) // 60, secs % 60)

import datetime
a = datetime.datetime(1,1,1,11,34,59)
b = a + datetime.timedelta(0,3) # days, seconds, then other fields.
print a.time()
print b.time()

11:34:59
11:35:02

b = a + datetime.timedelta(seconds=3)

import datetime

def addSecs (tm,secs):
    fulldate = datetime.datetime(1,1,1,tm.hour,tm.minute,tm.second)
    fulldate = fulldate + datetime.timedelta(0,3)
    return fulldate.time()

a = datetime.datetime.now().time()
b = addSecs (a,300)
print a
print b

16:38:04.314204
16:43:04

sometime = get_some_time() # the time to which you want to add 3 seconds
later = (datetime.combine(date.today(), sometime) + timedelta(seconds=3)).time()

def add_secs_to_time(timeval, secs_to_add):
    dummy_date = datetime.date(1, 1, 1)
    full_datetime = datetime.datetime.combine(dummy_date, timeval)
    added_datetime = full_datetime + datetime.timedelta(seconds=secs_to_add)
    return added_datetime.time()

(datetime.datetime.combine(datetime.date(1, 1, 1), timeval) + datetime.timedelta(seconds=secs_to_add)).time()

>>> b = a + datetime.timedelta(seconds=3000)
>>> b
datetime.datetime(1, 1, 1, 12, 24, 59)

>>> import datetime
>>> import nptime
>>> nptime.nptime(11, 34, 59) + datetime.timedelta(0, 3)
nptime(11, 35, 2)