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Apr 25th, 2018
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  1. function Mathlink(n,x,y) {if(x == y){return 0;}else{if(x > y){return -Math.floor((x-y)/n);}else{return Math.floor((y-x)/n);}}}
  2.  
  3. alert(Mathlink(2,12,24));
  4.  
  5. // Combien de n pour aller de x à y ?
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