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SteelK

Untitled

Dec 9th, 2016
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C++ 0.74 KB | None | 0 0
  1. #include "stdafx.h"
  2. #include <iostream>
  3.  
  4. using namespace std;
  5.  
  6. int main(){
  7.     //Блок расчета значений функции (1 подпункт задания)
  8.     int a = 1, b = 5, k;
  9.     long double mas[2][100], n;
  10.     cout << "Set n"<< endl;
  11.     cin >> n;
  12.     for (k = 0; (k <= n || k < 100); k++){
  13.         mas[0][k] = a + ((b - a) / n) * k;
  14.         if (mas[0][k] >= 0 && mas[0][k] <= 1)
  15.             mas[1][k] = -mas[0][k];
  16.         else if (mas[0][k] > 1 && mas[0][k] < 3)
  17.                 mas[1][k] = -mas[0][k] * mas[0][k] + 5 * mas[0][k] - 5;
  18.             else if (mas[0][k] >= 3 && mas[0][k] <= 5)
  19.                     mas[1][k] = mas[0][k] * mas[0][k] * mas[0][k] - 26;
  20.     }
  21.     //Блок вывода
  22.     for(int i = 0; i <= k; i++)
  23.         cout << mas[0][i] << ": " << mas[1][i] << endl;
  24.     cout << endl << endl;
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