Word Wrap Problem

import sys
sys.setrecursionlimit(10**9)
from functools import lru_cache
class Solution:
    def solveWordWrap(self, nums, k):
        @lru_cache()
        def help(c,i):#c points to the index where word can be started
            l=nums[i]
            ans=float('inf')
            rem=k-c#rem shows remaining valid length available . It means it avoids extra space when there is already another word
            if i==n-1:#If reached last word. Just ignore remaining spaces .Since it is end of line
                if l<=rem:#If we can insert return 0
                    return 0
                return (1+rem)**2 #Take new line return the remaining wasted space after (n-1) word
            if l<=rem: #If we can insert add word
               ans=min(ans,help(c+l+1,i+1)) # we are pointing next valid location in the line where new word can start
            if c!=0:#Not a Fresh line i.e. already some words are there
                ans=min(ans,help(0,i)+(1+rem)**2) #add space waste. Here I am adding (rem+1)**2 not rem**2 (think..)
            return ans
        return help(0,0)