LeastMajorityPrinciple - JavascriptModule0

// Least Majority Multiple
// Given five positive integers, their least majority multiple is the smallest positive integer that is divisible by at least three of them.
// Your task is to write a program that for given distinct integers a, b, c, d and e, returns their least majority multiple.
// For example if we have 1, 2, 3, 4 and 5 the majority multiple of the given five numbers is 4 because it is divisible by 1, 2, and 4.
// Another example: if we have 30, 42, 70, 35 and 90 the answer will be 210, because it is divisible by 30, 42, 70, and 35 - four out of five numbers, which is a majority.
// Input
// Read from the standard input
// The input data will consist of 5 lines.
// The numbers a, b, c, d and e will each be on a single line.
// The input data will always be valid and in the format described. There is no need to check it explicitly.
// Output
// Print on the standard output
// On the only output line you must print the least majority multiple of the given numbers.
// Constraints
// a, b, c, d and e will each be integer numbers between 1 and 100, inclusive.
// a, b, c, d and e will be distinct.
// Sample Tests
// Input Output
// 1
// 2
// 3
// 4
// 5 4
// 30
// 42
// 70
// 35
// 90 210
// JavaScript
// Credit to https://www.w3resource.com/javascript-exercises/javascript-math-exercise-10.php
const input = ['1', '2', '3', '4', '5'];
const print = this.print || console.log;
const gets = this.gets || ((arr, index) => () => arr[index++])(input, 0);
const numArray = [];
for (let i = 0; i < 5; i++) {
  numArray.push(+gets());
}
numArray.sort((a, b) => a - b);

function gcdTwoNumbers (x, y) {
  x = Math.abs(x);
  y = Math.abs(y);
  while (y) {
    const t = y;
    y = x % y;
    x = t;
  }
  return x;
}

function lcmTwoNumbers (x, y) {
  if ((typeof x !== 'number') || (typeof y !== 'number')) {
    return false;
  }
  return (!x || !y) ? 0 : Math.abs((x * y) / gcdTwoNumbers(x, y));
}

function lcm3 (x, y, z) {
  return lcmTwoNumbers(lcmTwoNumbers(x, y), z);
}
const a = numArray[0];
const b = numArray[1];
const c = numArray[2];
const d = numArray[3];
const e = numArray[4];
print(Math.min(lcm3(a, b, c), lcm3(a, b, d), lcm3(a, b, e), lcm3(a, c, d), lcm3(a, c, e), lcm3(a, d, e), lcm3(b, c, d), lcm3(b, c, e), lcm3(b, d, e), lcm3(c, d, e)));