sqrt 2 in the oeis

sqrt(2) = lim_{n->infinity}(1/(1-Sum_{k=1..n}(((-1)^(k-1)*binomial(n-1,
k-1))/f(k/n+s-1/n))/Sum_{k=1..n}(((-1)^(k-1)*binomial(n-1, k-1))/f(k/n +
s)))+s) where f(x)=x^2-2 and s=1. - Mats Granvik, Apr 22 2021

s=sqrt(-1)=I